X^2+105x-25=0

Solution for X^2+105x-25=0 equation:

X^2+105X-25=0

a = 1; b = 105; c = -25;
Δ = b2-4ac
Δ = 1052-4·1·(-25)
Δ = 11125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11125}=\sqrt{25*445}=\sqrt{25}*\sqrt{445}=5\sqrt{445}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(105)-5\sqrt{445}}{2*1}=\frac{-105-5\sqrt{445}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(105)+5\sqrt{445}}{2*1}=\frac{-105+5\sqrt{445}}{2}
$